35427005654013 has 20 divisors (see below), whose sum is σ = 53118558696060. Its totient is φ = 23530204484352.

The previous prime is 35427005654011. The next prime is 35427005654041. The reversal of 35427005654013 is 31045650072453.

35427005654013 is a `hidden beast` number, since 3 + 5 + 4 + 2 + 70 + 0 + 565 + 4 + 0 + 13 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 18971756612964 + 16455249041049 = 4355658^2 + 4056507^2 .

It is not a de Polignac number, because 35427005654013 - 2¹ = 35427005654011 is a prime.

It is a super-3 number, since 3×35427005654013³ (a number of 42 digits) contains 333 as substring.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 35427005654013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (35427005654011) by changing a digit.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 812934420 + ... + 812977997.

It is an arithmetic number, because the mean of its divisors is an integer number (2655927934803).

Almost surely, 2^{35427005654013} is an apocalyptic number.

It is an amenable number.

35427005654013 is a deficient number, since it is larger than the sum of its proper divisors (17691553042047).

35427005654013 is a wasteful number, since it uses less digits than its factorization.

35427005654013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1625912698 (or 1625912689 counting only the distinct ones).

The product of its (nonzero) digits is 1512000, while the sum is 45.

The spelling of 35427005654013 in words is "thirty-five trillion, four hundred twenty-seven billion, five million, six hundred fifty-four thousand, thirteen".