354300000433 has 4 divisors (see below), whose sum is σ = 354914039140. Its totient is φ = 353685961728.

The previous prime is 354300000377. The next prime is 354300000473. The reversal of 354300000433 is 334000003453.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 179519147809 + 174780852624 = 423697^2 + 418068^2 .

It is a cyclic number.

It is not a de Polignac number, because 354300000433 - 2²⁹ = 353763129521 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 354300000398 and 354300000407.

It is not an unprimeable number, because it can be changed into a prime (354300000473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 307018488 + ... + 307019641.

It is an arithmetic number, because the mean of its divisors is an integer number (88728509785).

Almost surely, 2^354300000433 is an apocalyptic number.

It is an amenable number.

354300000433 is a deficient number, since it is larger than the sum of its proper divisors (614038707).

354300000433 is an equidigital number, since it uses as much as digits as its factorization.

354300000433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 614038706.

The product of its (nonzero) digits is 6480, while the sum is 25.

Adding to 354300000433 its reverse (334000003453), we get a palindrome (688300003886).

The spelling of 354300000433 in words is "three hundred fifty-four billion, three hundred million, four hundred thirty-three", and thus it is an aban number.