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354402482513 is a prime number
BaseRepresentation
bin1010010100001000000…
…10001011100101010001
31020212202220210111000212
411022010002023211101
521301304013420023
6430451003053505
734414265253152
oct5120402134521
91225686714025
10354402482513
11127334a64652
1258828811295
132755c9c0571
1413220435929
1593437cce78
hex528408b951

354402482513 has 2 divisors, whose sum is σ = 354402482514. Its totient is φ = 354402482512.

The previous prime is 354402482479. The next prime is 354402482563. The reversal of 354402482513 is 315284204453.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 352257681169 + 2144801344 = 593513^2 + 46312^2 .

It is a cyclic number.

It is not a de Polignac number, because 354402482513 - 218 = 354402220369 is a prime.

It is a super-2 number, since 2×3544024825132 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (354402482563) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 177201241256 + 177201241257.

It is an arithmetic number, because the mean of its divisors is an integer number (177201241257).

Almost surely, 2354402482513 is an apocalyptic number.

It is an amenable number.

354402482513 is a deficient number, since it is larger than the sum of its proper divisors (1).

354402482513 is an equidigital number, since it uses as much as digits as its factorization.

354402482513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 460800, while the sum is 41.

Adding to 354402482513 its reverse (315284204453), we get a palindrome (669686686966).

The spelling of 354402482513 in words is "three hundred fifty-four billion, four hundred two million, four hundred eighty-two thousand, five hundred thirteen".