Base | Representation |
---|---|
bin | 1010010101011101000… |
… | …00001111000011100011 |
3 | 1020221121120112022221102 |
4 | 11022232200033003203 |
5 | 21304233420113011 |
6 | 431045414545015 |
7 | 34441036505516 |
oct | 5125640170343 |
9 | 1227546468842 |
10 | 355115004131 |
11 | 127670186698 |
12 | 589a736816b |
13 | 276444c51a4 |
14 | 1328ad0cd7d |
15 | 938612573b |
hex | 52ae80f0e3 |
355115004131 has 2 divisors, whose sum is σ = 355115004132. Its totient is φ = 355115004130.
The previous prime is 355115004121. The next prime is 355115004143. The reversal of 355115004131 is 131400511553.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 355115004131 - 234 = 337935134947 is a prime.
It is a super-2 number, since 2×3551150041312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 355115004094 and 355115004103.
It is not a weakly prime, because it can be changed into another prime (355115004121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 177557502065 + 177557502066.
It is an arithmetic number, because the mean of its divisors is an integer number (177557502066).
Almost surely, 2355115004131 is an apocalyptic number.
355115004131 is a deficient number, since it is larger than the sum of its proper divisors (1).
355115004131 is an equidigital number, since it uses as much as digits as its factorization.
355115004131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4500, while the sum is 29.
Adding to 355115004131 its reverse (131400511553), we get a palindrome (486515515684).
The spelling of 355115004131 in words is "three hundred fifty-five billion, one hundred fifteen million, four thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •