Base | Representation |
---|---|
bin | 101000011000110011001111… |
… | …1111011011001011011011100 |
3 | 1201120211210022111211121000111 |
4 | 1100301212133323121123130 |
5 | 333030423214123231134 |
6 | 3255320354251335404 |
7 | 134554063331024011 |
oct | 12061463773313334 |
9 | 1646753274747014 |
10 | 355252313102044 |
11 | a32157293790a6 |
12 | 33a16340a51564 |
13 | 1232c1c325c867 |
14 | 63a24374b7708 |
15 | 2b10ddbb17c64 |
hex | 143199fed96dc |
355252313102044 has 6 divisors (see below), whose sum is σ = 621691547928584. Its totient is φ = 177626156551020.
The previous prime is 355252313102039. The next prime is 355252313102047. The reversal of 355252313102044 is 440201313252553.
It is a junction number, because it is equal to n+sod(n) for n = 355252313101988 and 355252313102006.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (355252313102047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 44406539137752 + ... + 44406539137759.
Almost surely, 2355252313102044 is an apocalyptic number.
It is an amenable number.
355252313102044 is a deficient number, since it is larger than the sum of its proper divisors (266439234826540).
355252313102044 is a wasteful number, since it uses less digits than its factorization.
355252313102044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 88813078275515 (or 88813078275513 counting only the distinct ones).
The product of its (nonzero) digits is 432000, while the sum is 40.
Adding to 355252313102044 its reverse (440201313252553), we get a palindrome (795453626354597).
The spelling of 355252313102044 in words is "three hundred fifty-five trillion, two hundred fifty-two billion, three hundred thirteen million, one hundred two thousand, forty-four".
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