Base | Representation |
---|---|
bin | 110011101101000111100… |
… | …100111000100101011001 |
3 | 110120200021100111222102112 |
4 | 303231013210320211121 |
5 | 431203312013230311 |
6 | 11320142303442105 |
7 | 514464043344425 |
oct | 63550744704531 |
9 | 13520240458375 |
10 | 3553138805081 |
11 | 114a972252a08 |
12 | 494756bb6335 |
13 | 1ca0a0ab13b8 |
14 | c3d89665b85 |
15 | 6265a57d28b |
hex | 33b47938959 |
3553138805081 has 2 divisors, whose sum is σ = 3553138805082. Its totient is φ = 3553138805080.
The previous prime is 3553138804967. The next prime is 3553138805101. The reversal of 3553138805081 is 1805088313553.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3377108211481 + 176030593600 = 1837691^2 + 419560^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3553138805081 is a prime.
It is a super-2 number, since 2×35531388050812 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3553131805081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1776569402540 + 1776569402541.
It is an arithmetic number, because the mean of its divisors is an integer number (1776569402541).
Almost surely, 23553138805081 is an apocalyptic number.
It is an amenable number.
3553138805081 is a deficient number, since it is larger than the sum of its proper divisors (1).
3553138805081 is an equidigital number, since it uses as much as digits as its factorization.
3553138805081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728000, while the sum is 50.
The spelling of 3553138805081 in words is "three trillion, five hundred fifty-three billion, one hundred thirty-eight million, eight hundred five thousand, eighty-one".
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