Base | Representation |
---|---|
bin | 1101011101001100… |
… | …1110011100010011 |
3 | 100022201212210101021 |
4 | 3113103032130103 |
5 | 24344202010311 |
6 | 1354232420311 |
7 | 155340460201 |
oct | 32723163423 |
9 | 10281783337 |
10 | 3612141331 |
11 | 1593a61277 |
12 | 849847697 |
13 | 457471546 |
14 | 263a30071 |
15 | 1621ae171 |
hex | d74ce713 |
3612141331 has 4 divisors (see below), whose sum is σ = 3612649464. Its totient is φ = 3611633200.
The previous prime is 3612141307. The next prime is 3612141343. The reversal of 3612141331 is 1331412163.
3612141331 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1331412163 = 743 ⋅1791941.
It is a cyclic number.
It is not a de Polignac number, because 3612141331 - 213 = 3612133139 is a prime.
It is a super-2 number, since 2×36121413312 = 26095129990236903122, which contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3612141296 and 3612141305.
It is not an unprimeable number, because it can be changed into a prime (3612141301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 243250 + ... + 257671.
It is an arithmetic number, because the mean of its divisors is an integer number (903162366).
Almost surely, 23612141331 is an apocalyptic number.
3612141331 is a deficient number, since it is larger than the sum of its proper divisors (508133).
3612141331 is an equidigital number, since it uses as much as digits as its factorization.
3612141331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 508132.
The product of its digits is 1296, while the sum is 25.
The square root of 3612141331 is about 60101.0925940619. The cubic root of 3612141331 is about 1534.3398974668.
Adding to 3612141331 its reverse (1331412163), we get a palindrome (4943553494).
The spelling of 3612141331 in words is "three billion, six hundred twelve million, one hundred forty-one thousand, three hundred thirty-one".
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