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361225433 is a prime number
BaseRepresentation
bin10101100001111…
…101110011011001
3221011201011010202
4111201331303121
51214433203213
655502151545
711644236242
oct2541756331
9834634122
10361225433
111759a2018
12a0b825b5
1359ab677a
1435d8dcc9
1521aa4b58
hex1587dcd9

361225433 has 2 divisors, whose sum is σ = 361225434. Its totient is φ = 361225432.

The previous prime is 361225427. The next prime is 361225453. The reversal of 361225433 is 334522163.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 219424969 + 141800464 = 14813^2 + 11908^2 .

It is a cyclic number.

It is not a de Polignac number, because 361225433 - 28 = 361225177 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 361225396 and 361225405.

It is not a weakly prime, because it can be changed into another prime (361225453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 180612716 + 180612717.

It is an arithmetic number, because the mean of its divisors is an integer number (180612717).

Almost surely, 2361225433 is an apocalyptic number.

It is an amenable number.

361225433 is a deficient number, since it is larger than the sum of its proper divisors (1).

361225433 is an equidigital number, since it uses as much as digits as its factorization.

361225433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 12960, while the sum is 29.

The square root of 361225433 is about 19005.9315215014. The cubic root of 361225433 is about 712.1849198021.

Adding to 361225433 its reverse (334522163), we get a palindrome (695747596).

The spelling of 361225433 in words is "three hundred sixty-one million, two hundred twenty-five thousand, four hundred thirty-three".