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361450142113 is a prime number
BaseRepresentation
bin1010100001010000001…
…10110111100110100001
31021112222002012200111111
411100220012313212201
521410222214021423
6434014202543321
735054033341534
oct5205006674641
91245862180444
10361450142113
1112a321200615
125a074b07b41
1328113b42548
14136cc43aa1b
1596073ad60d
hex54281b79a1

361450142113 has 2 divisors, whose sum is σ = 361450142114. Its totient is φ = 361450142112.

The previous prime is 361450142107. The next prime is 361450142153. The reversal of 361450142113 is 311241054163.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 310257912064 + 51192230049 = 557008^2 + 226257^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-361450142113 is a prime.

It is a super-2 number, since 2×3614501421132 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (361450142153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 180725071056 + 180725071057.

It is an arithmetic number, because the mean of its divisors is an integer number (180725071057).

Almost surely, 2361450142113 is an apocalyptic number.

It is an amenable number.

361450142113 is a deficient number, since it is larger than the sum of its proper divisors (1).

361450142113 is an equidigital number, since it uses as much as digits as its factorization.

361450142113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 361450142113 its reverse (311241054163), we get a palindrome (672691196276).

The spelling of 361450142113 in words is "three hundred sixty-one billion, four hundred fifty million, one hundred forty-two thousand, one hundred thirteen".