Base | Representation |
---|---|
bin | 110101000001110110100… |
… | …100010000111100111001 |
3 | 110220101010002111000010121 |
4 | 311001312210100330321 |
5 | 434201130100010423 |
6 | 11430030350213241 |
7 | 524164504354354 |
oct | 65016644207471 |
9 | 13811102430117 |
10 | 3644121485113 |
11 | 118551063805a |
12 | 4aa308ab4221 |
13 | 205840388245 |
14 | c853ac8329b |
15 | 64bd2d1945d |
hex | 35076910f39 |
3644121485113 has 2 divisors, whose sum is σ = 3644121485114. Its totient is φ = 3644121485112.
The previous prime is 3644121485077. The next prime is 3644121485119. The reversal of 3644121485113 is 3115841214463.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2790129255424 + 853992229689 = 1670368^2 + 924117^2 .
It is a cyclic number.
It is not a de Polignac number, because 3644121485113 - 213 = 3644121476921 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3644121485113.
It is not a weakly prime, because it can be changed into another prime (3644121485119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1822060742556 + 1822060742557.
It is an arithmetic number, because the mean of its divisors is an integer number (1822060742557).
Almost surely, 23644121485113 is an apocalyptic number.
It is an amenable number.
3644121485113 is a deficient number, since it is larger than the sum of its proper divisors (1).
3644121485113 is an equidigital number, since it uses as much as digits as its factorization.
3644121485113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 276480, while the sum is 43.
Adding to 3644121485113 its reverse (3115841214463), we get a palindrome (6759962699576).
The spelling of 3644121485113 in words is "three trillion, six hundred forty-four billion, one hundred twenty-one million, four hundred eighty-five thousand, one hundred thirteen".
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