Search a number
-
+
364750076378131 is a prime number
BaseRepresentation
bin101001011101111001111111…
…0101110111111110000010011
31202211110202200222001210012221
41102323303332232333300103
5340302031124023100011
63331431512152401511
7136554215630600653
oct12273637656776023
91684422628053187
10364750076378131
11a6247703111964
1234aab0126a6297
131286aa27a4b332
14660ddd8306363
152c27ebe8a4971
hex14bbcfebbfc13

364750076378131 has 2 divisors, whose sum is σ = 364750076378132. Its totient is φ = 364750076378130.

The previous prime is 364750076378047. The next prime is 364750076378167. The reversal of 364750076378131 is 131873670057463.

It is a strong prime.

It is an emirp because it is prime and its reverse (131873670057463) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 364750076378131 - 215 = 364750076345363 is a prime.

It is a super-2 number, since 2×3647500763781312 (a number of 30 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 364750076378131.

It is not a weakly prime, because it can be changed into another prime (364750076378731) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 182375038189065 + 182375038189066.

It is an arithmetic number, because the mean of its divisors is an integer number (182375038189066).

Almost surely, 2364750076378131 is an apocalyptic number.

364750076378131 is a deficient number, since it is larger than the sum of its proper divisors (1).

364750076378131 is an equidigital number, since it uses as much as digits as its factorization.

364750076378131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 53343360, while the sum is 61.

The spelling of 364750076378131 in words is "three hundred sixty-four trillion, seven hundred fifty billion, seventy-six million, three hundred seventy-eight thousand, one hundred thirty-one".