Base | Representation |
---|---|
bin | 100010000110110011… |
… | …101011000101001001 |
3 | 10111112012200110021111 |
4 | 202012303223011021 |
5 | 1100000041243423 |
6 | 24453524210321 |
7 | 2434341012511 |
oct | 420663530511 |
9 | 114465613244 |
10 | 36621431113 |
11 | 14592930253 |
12 | 71205399a1 |
13 | 35b8121387 |
14 | 1ab59bc841 |
15 | e450b460d |
hex | 886ceb149 |
36621431113 has 2 divisors, whose sum is σ = 36621431114. Its totient is φ = 36621431112.
The previous prime is 36621431083. The next prime is 36621431131. The reversal of 36621431113 is 31113412663.
Together with next prime (36621431131) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 22358622784 + 14262808329 = 149528^2 + 119427^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-36621431113 is a prime.
It is a super-2 number, since 2×366214311132 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (36621431153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 18310715556 + 18310715557.
It is an arithmetic number, because the mean of its divisors is an integer number (18310715557).
Almost surely, 236621431113 is an apocalyptic number.
It is an amenable number.
36621431113 is a deficient number, since it is larger than the sum of its proper divisors (1).
36621431113 is an equidigital number, since it uses as much as digits as its factorization.
36621431113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 7776, while the sum is 31.
Adding to 36621431113 its reverse (31113412663), we get a palindrome (67734843776).
The spelling of 36621431113 in words is "thirty-six billion, six hundred twenty-one million, four hundred thirty-one thousand, one hundred thirteen".
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