Base | Representation |
---|---|
bin | 110101010101101010101… |
… | …011000101101110001100 |
3 | 110222102000210201011120220 |
4 | 311111222223011232030 |
5 | 440023213034042022 |
6 | 11443505433511340 |
7 | 525546643413015 |
oct | 65255253055614 |
9 | 13872023634526 |
10 | 3665396784012 |
11 | 1193538a23007 |
12 | 4b2465b72550 |
13 | 20785102c9c2 |
14 | c959869a00c |
15 | 6552a9e685c |
hex | 3556aac5b8c |
3665396784012 has 24 divisors (see below), whose sum is σ = 8552953224816. Its totient is φ = 1221747395328.
The previous prime is 3665396783957. The next prime is 3665396784013. The reversal of 3665396784012 is 2104876935663.
It is a super-2 number, since 2×36653967840122 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (3665396784013) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6144673 + ... + 6714744.
It is an arithmetic number, because the mean of its divisors is an integer number (356373051034).
It is a 1-persistent number, because it is pandigital, but 2⋅3665396784012 = 7330793568024 is not.
Almost surely, 23665396784012 is an apocalyptic number.
It is an amenable number.
3665396784012 is an abundant number, since it is smaller than the sum of its proper divisors (4887556440804).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3665396784012 is a wasteful number, since it uses less digits than its factorization.
3665396784012 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12883177 (or 12883175 counting only the distinct ones).
The product of its (nonzero) digits is 39191040, while the sum is 60.
The spelling of 3665396784012 in words is "three trillion, six hundred sixty-five billion, three hundred ninety-six million, seven hundred eighty-four thousand, twelve".
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