Base | Representation |
---|---|
bin | 1011000100000100010… |
… | …01011001001101011001 |
3 | 1100100012122122110210112 |
4 | 11202002021121031121 |
5 | 22212011444411211 |
6 | 450344552454105 |
7 | 36315144656531 |
oct | 5420211311531 |
9 | 1310178573715 |
10 | 380140622681 |
11 | 137242520276 |
12 | 618103aa335 |
13 | 29b0212b2c1 |
14 | 145828444c1 |
15 | 9d4d1a888b |
hex | 5882259359 |
380140622681 has 2 divisors, whose sum is σ = 380140622682. Its totient is φ = 380140622680.
The previous prime is 380140622677. The next prime is 380140622753. The reversal of 380140622681 is 186226041083.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 283120832281 + 97019790400 = 532091^2 + 311480^2 .
It is a cyclic number.
It is not a de Polignac number, because 380140622681 - 22 = 380140622677 is a prime.
It is a super-2 number, since 2×3801406226812 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (380140622881) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 190070311340 + 190070311341.
It is an arithmetic number, because the mean of its divisors is an integer number (190070311341).
Almost surely, 2380140622681 is an apocalyptic number.
It is an amenable number.
380140622681 is a deficient number, since it is larger than the sum of its proper divisors (1).
380140622681 is an equidigital number, since it uses as much as digits as its factorization.
380140622681 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 110592, while the sum is 41.
The spelling of 380140622681 in words is "three hundred eighty billion, one hundred forty million, six hundred twenty-two thousand, six hundred eighty-one".
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