Base | Representation |
---|---|
bin | 1110001010111101… |
… | …0100001001110011 |
3 | 100211002222222020202 |
4 | 3202233110021303 |
5 | 30242314213011 |
6 | 1425250025415 |
7 | 163160632553 |
oct | 34257241163 |
9 | 10732888222 |
10 | 3804054131 |
11 | 1682320199 |
12 | 8a1b7826b |
13 | 488156807 |
14 | 281309163 |
15 | 173e6c23b |
hex | e2bd4273 |
3804054131 has 2 divisors, whose sum is σ = 3804054132. Its totient is φ = 3804054130.
The previous prime is 3804054103. The next prime is 3804054139. The reversal of 3804054131 is 1314504083.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3804054131 is a prime.
It is a super-2 number, since 2×38040541312 = 28941655663156330322, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3804054094 and 3804054103.
It is not a weakly prime, because it can be changed into another prime (3804054139) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1902027065 + 1902027066.
It is an arithmetic number, because the mean of its divisors is an integer number (1902027066).
Almost surely, 23804054131 is an apocalyptic number.
3804054131 is a deficient number, since it is larger than the sum of its proper divisors (1).
3804054131 is an equidigital number, since it uses as much as digits as its factorization.
3804054131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5760, while the sum is 29.
The square root of 3804054131 is about 61677.0146083612. The cubic root of 3804054131 is about 1561.0455038148.
The spelling of 3804054131 in words is "three billion, eight hundred four million, fifty-four thousand, one hundred thirty-one".
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