Base | Representation |
---|---|
bin | 110111010110111111010… |
… | …101001010101101111011 |
3 | 111110200110010220222010112 |
4 | 313112333111022231323 |
5 | 444312104022213024 |
6 | 12031352345534535 |
7 | 541564003631162 |
oct | 67267725125573 |
9 | 14420403828115 |
10 | 3804256054139 |
11 | 1237415402992 |
12 | 5153597a444b |
13 | 2179804801b8 |
14 | d21ac5c63d9 |
15 | 68e564d900e |
hex | 375bf54ab7b |
3804256054139 has 2 divisors, whose sum is σ = 3804256054140. Its totient is φ = 3804256054138.
The previous prime is 3804256054133. The next prime is 3804256054211. The reversal of 3804256054139 is 9314506524083.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3804256054139 is a prime.
It is not a weakly prime, because it can be changed into another prime (3804256054133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1902128027069 + 1902128027070.
It is an arithmetic number, because the mean of its divisors is an integer number (1902128027070).
Almost surely, 23804256054139 is an apocalyptic number.
3804256054139 is a deficient number, since it is larger than the sum of its proper divisors (1).
3804256054139 is an equidigital number, since it uses as much as digits as its factorization.
3804256054139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3110400, while the sum is 50.
The spelling of 3804256054139 in words is "three trillion, eight hundred four billion, two hundred fifty-six million, fifty-four thousand, one hundred thirty-nine".
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