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3813284646217 is a prime number
BaseRepresentation
bin110111011111011001011…
…110100000110101001001
3111111112202100210222002201
4313133121132200311021
5444434101332134332
612035444312000201
7542333514455104
oct67373136406511
914445670728081
103813284646217
111240228852832
12517059390061
1321878bb31687
14d27c772173b
15692d3e625e7
hex377d97a0d49

3813284646217 has 2 divisors, whose sum is σ = 3813284646218. Its totient is φ = 3813284646216.

The previous prime is 3813284646211. The next prime is 3813284646221. The reversal of 3813284646217 is 7126464823183.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2577232101376 + 1236052544841 = 1605376^2 + 1111779^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3813284646217 is a prime.

It is a super-2 number, since 2×38132846462172 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (3813284646211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1906642323108 + 1906642323109.

It is an arithmetic number, because the mean of its divisors is an integer number (1906642323109).

Almost surely, 23813284646217 is an apocalyptic number.

It is an amenable number.

3813284646217 is a deficient number, since it is larger than the sum of its proper divisors (1).

3813284646217 is an equidigital number, since it uses as much as digits as its factorization.

3813284646217 is an evil number, because the sum of its binary digits is even.

The product of its digits is 9289728, while the sum is 55.

The spelling of 3813284646217 in words is "three trillion, eight hundred thirteen billion, two hundred eighty-four million, six hundred forty-six thousand, two hundred seventeen".