38170450448117 has 4 divisors (see below), whose sum is σ = 41106638944140. Its totient is φ = 35234261952096.

The previous prime is 38170450448113. The next prime is 38170450448129. The reversal of 38170450448117 is 71184405407183.

38170450448117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8712379402276 + 29458071045841 = 2951674^2 + 5427529^2 .

It is a cyclic number.

It is not a de Polignac number, because 38170450448117 - 2² = 38170450448113 is a prime.

It is a super-2 number, since 2×38170450448117² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (38170450448113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1468094247992 + ... + 1468094248017.

It is an arithmetic number, because the mean of its divisors is an integer number (10276659736035).

Almost surely, 2^{38170450448117} is an apocalyptic number.

It is an amenable number.

38170450448117 is a deficient number, since it is larger than the sum of its proper divisors (2936188496023).

38170450448117 is a wasteful number, since it uses less digits than its factorization.

38170450448117 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2936188496022.

The product of its (nonzero) digits is 3010560, while the sum is 53.

The spelling of 38170450448117 in words is "thirty-eight trillion, one hundred seventy billion, four hundred fifty million, four hundred forty-eight thousand, one hundred seventeen".