Base | Representation |
---|---|
bin | 1011001000101000101… |
… | …10000011101000000001 |
3 | 1100120112121000021020201 |
4 | 11210110112003220001 |
5 | 22232022403300211 |
6 | 451432212405201 |
7 | 36433010242531 |
oct | 5442426035001 |
9 | 1316477007221 |
10 | 382593415681 |
11 | 138291010a24 |
12 | 62195916801 |
13 | 2a10333c6c9 |
14 | 147364c74c1 |
15 | 9e436ac0c1 |
hex | 5914583a01 |
382593415681 has 2 divisors, whose sum is σ = 382593415682. Its totient is φ = 382593415680.
The previous prime is 382593415651. The next prime is 382593415703. The reversal of 382593415681 is 186514395283.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 380960528400 + 1632887281 = 617220^2 + 40409^2 .
It is a cyclic number.
It is not a de Polignac number, because 382593415681 - 27 = 382593415553 is a prime.
It is a super-2 number, since 2×3825934156812 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (382593415651) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 191296707840 + 191296707841.
It is an arithmetic number, because the mean of its divisors is an integer number (191296707841).
Almost surely, 2382593415681 is an apocalyptic number.
It is an amenable number.
382593415681 is a deficient number, since it is larger than the sum of its proper divisors (1).
382593415681 is an equidigital number, since it uses as much as digits as its factorization.
382593415681 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6220800, while the sum is 55.
The spelling of 382593415681 in words is "three hundred eighty-two billion, five hundred ninety-three million, four hundred fifteen thousand, six hundred eighty-one".
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