Base | Representation |
---|---|
bin | 10001011011111101011001… |
… | …11101000110000001100011 |
3 | 12000202122202111102101000201 |
4 | 20231332230331012001203 |
5 | 20011212131113414003 |
6 | 213315005203130031 |
7 | 11035160626455523 |
oct | 1055765475060143 |
9 | 160678674371021 |
10 | 38344074748003 |
11 | 112436a3627062 |
12 | 4373409073917 |
13 | 1851aa517794b |
14 | 967c12589683 |
15 | 46763d9c2b1d |
hex | 22dfacf46063 |
38344074748003 has 2 divisors, whose sum is σ = 38344074748004. Its totient is φ = 38344074748002.
The previous prime is 38344074747977. The next prime is 38344074748061. The reversal of 38344074748003 is 30084747044383.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 38344074748003 - 233 = 38335484813411 is a prime.
It is not a weakly prime, because it can be changed into another prime (38344074748403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19172037374001 + 19172037374002.
It is an arithmetic number, because the mean of its divisors is an integer number (19172037374002).
Almost surely, 238344074748003 is an apocalyptic number.
38344074748003 is a deficient number, since it is larger than the sum of its proper divisors (1).
38344074748003 is an equidigital number, since it uses as much as digits as its factorization.
38344074748003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21676032, while the sum is 55.
The spelling of 38344074748003 in words is "thirty-eight trillion, three hundred forty-four billion, seventy-four million, seven hundred forty-eight thousand, three".
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