Base | Representation |
---|---|
bin | 10001011101100111101010… |
… | …10101110101000001001011 |
3 | 12000222010000100012202222001 |
4 | 20232303311111311001023 |
5 | 20013131000141010342 |
6 | 213401122133411431 |
7 | 11042250434226256 |
oct | 1056636525650113 |
9 | 160863010182861 |
10 | 38401123766347 |
11 | 11265909283a01 |
12 | 438248a799b77 |
13 | 1857297423c34 |
14 | 96a8a515609d |
15 | 468d7c1158b7 |
hex | 22ecf557504b |
38401123766347 has 2 divisors, whose sum is σ = 38401123766348. Its totient is φ = 38401123766346.
The previous prime is 38401123766323. The next prime is 38401123766417. The reversal of 38401123766347 is 74366732110483.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-38401123766347 is a prime.
It is not a weakly prime, because it can be changed into another prime (38401123266347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19200561883173 + 19200561883174.
It is an arithmetic number, because the mean of its divisors is an integer number (19200561883174).
Almost surely, 238401123766347 is an apocalyptic number.
38401123766347 is a deficient number, since it is larger than the sum of its proper divisors (1).
38401123766347 is an equidigital number, since it uses as much as digits as its factorization.
38401123766347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12192768, while the sum is 55.
The spelling of 38401123766347 in words is "thirty-eight trillion, four hundred one billion, one hundred twenty-three million, seven hundred sixty-six thousand, three hundred forty-seven".
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