Base | Representation |
---|---|
bin | 10001011101101000100101… |
… | …00000110001001111000111 |
3 | 12000222011021110010020122102 |
4 | 20232310102200301033013 |
5 | 20013133000433024303 |
6 | 213401242455222315 |
7 | 11042265526145003 |
oct | 1056642240611707 |
9 | 160864243106572 |
10 | 38401613173703 |
11 | 1126603a56599a |
12 | 43825a667799b |
13 | 185734493a7a0 |
14 | 96a910151703 |
15 | 468daa08a288 |
hex | 22ed128313c7 |
38401613173703 has 4 divisors (see below), whose sum is σ = 41355583417848. Its totient is φ = 35447642929560.
The previous prime is 38401613173631. The next prime is 38401613173733. The reversal of 38401613173703 is 30737131610483.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 38401613173703 - 212 = 38401613169607 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (38401613173733) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1476985122053 + ... + 1476985122078.
It is an arithmetic number, because the mean of its divisors is an integer number (10338895854462).
Almost surely, 238401613173703 is an apocalyptic number.
38401613173703 is a deficient number, since it is larger than the sum of its proper divisors (2953970244145).
38401613173703 is a wasteful number, since it uses less digits than its factorization.
38401613173703 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2953970244144.
The product of its (nonzero) digits is 762048, while the sum is 47.
The spelling of 38401613173703 in words is "thirty-eight trillion, four hundred one billion, six hundred thirteen million, one hundred seventy-three thousand, seven hundred three".
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