Base | Representation |
---|---|
bin | 1011001011100001000… |
… | …01100010101000100011 |
3 | 1100201112101001100021021 |
4 | 11211300201202220203 |
5 | 22243204310231042 |
6 | 452245455510311 |
7 | 36516226350211 |
oct | 5456041425043 |
9 | 1321471040237 |
10 | 384139930147 |
11 | 138a04a81156 |
12 | 62547828397 |
13 | 2a2bb86971c |
14 | 14841a57cb1 |
15 | 9ed4343867 |
hex | 5970862a23 |
384139930147 has 2 divisors, whose sum is σ = 384139930148. Its totient is φ = 384139930146.
The previous prime is 384139930133. The next prime is 384139930157. The reversal of 384139930147 is 741039931483.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-384139930147 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 384139930094 and 384139930103.
It is not a weakly prime, because it can be changed into another prime (384139930157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 192069965073 + 192069965074.
It is an arithmetic number, because the mean of its divisors is an integer number (192069965074).
Almost surely, 2384139930147 is an apocalyptic number.
384139930147 is a deficient number, since it is larger than the sum of its proper divisors (1).
384139930147 is an equidigital number, since it uses as much as digits as its factorization.
384139930147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1959552, while the sum is 52.
The spelling of 384139930147 in words is "three hundred eighty-four billion, one hundred thirty-nine million, nine hundred thirty thousand, one hundred forty-seven".
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