Base | Representation |
---|---|
bin | 10001011110010011001010… |
… | …00010100110111101110011 |
3 | 12001001100021120012001211001 |
4 | 20233021211002212331303 |
5 | 20014021304442101343 |
6 | 213415543052302431 |
7 | 11044035152156551 |
oct | 1057114502467563 |
9 | 161040246161731 |
10 | 38424472612723 |
11 | 1127480007a85a |
12 | 4386b06171a17 |
13 | 1859548854172 |
14 | 96ba7c0d0bd1 |
15 | 469796d8244d |
hex | 22f2650a6f73 |
38424472612723 has 2 divisors, whose sum is σ = 38424472612724. Its totient is φ = 38424472612722.
The previous prime is 38424472612703. The next prime is 38424472612787. The reversal of 38424472612723 is 32721627442483.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 38424472612723 - 241 = 36225449357171 is a prime.
It is a super-3 number, since 3×384244726127233 (a number of 42 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (38424472612703) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19212236306361 + 19212236306362.
It is an arithmetic number, because the mean of its divisors is an integer number (19212236306362).
Almost surely, 238424472612723 is an apocalyptic number.
38424472612723 is a deficient number, since it is larger than the sum of its proper divisors (1).
38424472612723 is an equidigital number, since it uses as much as digits as its factorization.
38424472612723 is an evil number, because the sum of its binary digits is even.
The product of its digits is 21676032, while the sum is 55.
The spelling of 38424472612723 in words is "thirty-eight trillion, four hundred twenty-four billion, four hundred seventy-two million, six hundred twelve thousand, seven hundred twenty-three".
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