3851133312041 has 2 divisors, whose sum is σ = 3851133312042. Its totient is φ = 3851133312040.

The previous prime is 3851133311953. The next prime is 3851133312113. The reversal of 3851133312041 is 1402133311583.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3392580874816 + 458552437225 = 1841896^2 + 677165^2 .

It is an emirp because it is prime and its reverse (1402133311583) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3851133312041 is a prime.

It is a super-2 number, since 2×3851133312041² (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3851133311992 and 3851133312010.

It is not a weakly prime, because it can be changed into another prime (3851133312541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1925566656020 + 1925566656021.

It is an arithmetic number, because the mean of its divisors is an integer number (1925566656021).

Almost surely, 2^{3851133312041} is an apocalyptic number.

It is an amenable number.

3851133312041 is a deficient number, since it is larger than the sum of its proper divisors (1).

3851133312041 is an equidigital number, since it uses as much as digits as its factorization.

3851133312041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25920, while the sum is 35.

The spelling of 3851133312041 in words is "three trillion, eight hundred fifty-one billion, one hundred thirty-three million, three hundred twelve thousand, forty-one".