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38853850433 is a prime number
BaseRepresentation
bin100100001011110111…
…101011010101000001
310201021210101002212112
4210023313223111001
51114033041203213
625503232505105
72543556164606
oct441367532501
9121253332775
1038853850433
1115528a929a2
1276440ab195
133882793c58
141c482986ad
151026086ea8
hex90bdeb541

38853850433 has 2 divisors, whose sum is σ = 38853850434. Its totient is φ = 38853850432.

The previous prime is 38853850363. The next prime is 38853850513. The reversal of 38853850433 is 33405835883.

38853850433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 35423756944 + 3430093489 = 188212^2 + 58567^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-38853850433 is a prime.

It is not a weakly prime, because it can be changed into another prime (38853850333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19426925216 + 19426925217.

It is an arithmetic number, because the mean of its divisors is an integer number (19426925217).

Almost surely, 238853850433 is an apocalyptic number.

It is an amenable number.

38853850433 is a deficient number, since it is larger than the sum of its proper divisors (1).

38853850433 is an equidigital number, since it uses as much as digits as its factorization.

38853850433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4147200, while the sum is 50.

The spelling of 38853850433 in words is "thirty-eight billion, eight hundred fifty-three million, eight hundred fifty thousand, four hundred thirty-three".