Base | Representation |
---|---|
bin | 111000111001100100110… |
… | …101111100010000011001 |
3 | 111211210200102202100000120 |
4 | 320321210311330100121 |
5 | 1003030402144221101 |
6 | 12152140344223453 |
7 | 552332136322602 |
oct | 70714465742031 |
9 | 14753612670016 |
10 | 3910112101401 |
11 | 12782a6387a70 |
12 | 53198076ab89 |
13 | 22495029615c |
14 | d73712a2da9 |
15 | 6ba9e8c3b36 |
hex | 38e64d7c419 |
3910112101401 has 32 divisors (see below), whose sum is σ = 5733483429888. Its totient is φ = 2350586629440.
The previous prime is 3910112101397. The next prime is 3910112101409. The reversal of 3910112101401 is 1041012110193.
3910112101401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3910112101401 - 22 = 3910112101397 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (3910112101409) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 19333066 + ... + 19534268.
It is an arithmetic number, because the mean of its divisors is an integer number (179171357184).
Almost surely, 23910112101401 is an apocalyptic number.
It is an amenable number.
3910112101401 is a deficient number, since it is larger than the sum of its proper divisors (1823371328487).
3910112101401 is a wasteful number, since it uses less digits than its factorization.
3910112101401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 205981.
The product of its (nonzero) digits is 216, while the sum is 24.
Adding to 3910112101401 its reverse (1041012110193), we get a palindrome (4951124211594).
The spelling of 3910112101401 in words is "three trillion, nine hundred ten billion, one hundred twelve million, one hundred one thousand, four hundred one".
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