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39112221111193 is a prime number
BaseRepresentation
bin10001110010010100001100…
…00010111011001110011001
312010111002110221022200222001
420321022012002323032121
520111303312101024233
6215103523433401001
711144523205021666
oct1071120602731631
9163432427280861
1039112221111193
111150a444188a7a
124478263869161
1318a9360a0c5c9
1499308222aa6d
1547c5ea58a27d
hex2392860bb399

39112221111193 has 2 divisors, whose sum is σ = 39112221111194. Its totient is φ = 39112221111192.

The previous prime is 39112221111043. The next prime is 39112221111221. The reversal of 39112221111193 is 39111112221193.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 34438271138569 + 4673949972624 = 5868413^2 + 2161932^2 .

It is a cyclic number.

It is not a de Polignac number, because 39112221111193 - 217 = 39112220980121 is a prime.

It is not a weakly prime, because it can be changed into another prime (39112221171193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19556110555596 + 19556110555597.

It is an arithmetic number, because the mean of its divisors is an integer number (19556110555597).

Almost surely, 239112221111193 is an apocalyptic number.

It is an amenable number.

39112221111193 is a deficient number, since it is larger than the sum of its proper divisors (1).

39112221111193 is an equidigital number, since it uses as much as digits as its factorization.

39112221111193 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5832, while the sum is 37.

Subtracting from 39112221111193 its reverse (39111112221193), we obtain a square (1108890000 = 333002).

The spelling of 39112221111193 in words is "thirty-nine trillion, one hundred twelve billion, two hundred twenty-one million, one hundred eleven thousand, one hundred ninety-three".