Base | Representation |
---|---|
bin | 111000111011011001001… |
… | …111110100110110010001 |
3 | 111211222201112120002102122 |
4 | 320323121033310312101 |
5 | 1003043402122400412 |
6 | 12153102230424025 |
7 | 552431422133435 |
oct | 70733117646621 |
9 | 14758645502378 |
10 | 3912065043857 |
11 | 12791088035a3 |
12 | 532226802015 |
13 | 224ba1a754c9 |
14 | d74b87cc9c5 |
15 | 6bb6608d572 |
hex | 38ed93f4d91 |
3912065043857 has 16 divisors (see below), whose sum is σ = 4163393520000. Its totient is φ = 3665493120384.
The previous prime is 3912065043791. The next prime is 3912065043869. The reversal of 3912065043857 is 7583405602193.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 3912065043857 - 236 = 3843345567121 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3912065043799 and 3912065043808.
It is not an unprimeable number, because it can be changed into a prime (3912065042857) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2305757 + ... + 3625002.
It is an arithmetic number, because the mean of its divisors is an integer number (260212095000).
It is a 1-persistent number, because it is pandigital, but 2⋅3912065043857 = 7824130087714 is not.
Almost surely, 23912065043857 is an apocalyptic number.
It is an amenable number.
3912065043857 is a deficient number, since it is larger than the sum of its proper divisors (251328476143).
3912065043857 is a wasteful number, since it uses less digits than its factorization.
3912065043857 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5931160.
The product of its (nonzero) digits is 5443200, while the sum is 53.
The spelling of 3912065043857 in words is "three trillion, nine hundred twelve billion, sixty-five million, forty-three thousand, eight hundred fifty-seven".
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