Base | Representation |
---|---|
bin | 111000111101110111111… |
… | …000010011011101010001 |
3 | 111212020121000110210100012 |
4 | 320331313320103131101 |
5 | 1003114324433030441 |
6 | 12154222302004305 |
7 | 552554366560106 |
oct | 70756770233521 |
9 | 14766530423305 |
10 | 3914726455121 |
11 | 127a254033239 |
12 | 532849b76695 |
13 | 22520726a881 |
14 | d768c058aad |
15 | 6bc6ea4e9eb |
hex | 38f77e13751 |
3914726455121 has 2 divisors, whose sum is σ = 3914726455122. Its totient is φ = 3914726455120.
The previous prime is 3914726455111. The next prime is 3914726455169. The reversal of 3914726455121 is 1215546274193.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2452293360400 + 1462433094721 = 1565980^2 + 1209311^2 .
It is a cyclic number.
It is not a de Polignac number, because 3914726455121 - 210 = 3914726454097 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3914726455121.
It is not a weakly prime, because it can be changed into another prime (3914726455111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1957363227560 + 1957363227561.
It is an arithmetic number, because the mean of its divisors is an integer number (1957363227561).
Almost surely, 23914726455121 is an apocalyptic number.
It is an amenable number.
3914726455121 is a deficient number, since it is larger than the sum of its proper divisors (1).
3914726455121 is an equidigital number, since it uses as much as digits as its factorization.
3914726455121 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1814400, while the sum is 50.
The spelling of 3914726455121 in words is "three trillion, nine hundred fourteen billion, seven hundred twenty-six million, four hundred fifty-five thousand, one hundred twenty-one".
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