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3914726455121 is a prime number
BaseRepresentation
bin111000111101110111111…
…000010011011101010001
3111212020121000110210100012
4320331313320103131101
51003114324433030441
612154222302004305
7552554366560106
oct70756770233521
914766530423305
103914726455121
11127a254033239
12532849b76695
1322520726a881
14d768c058aad
156bc6ea4e9eb
hex38f77e13751

3914726455121 has 2 divisors, whose sum is σ = 3914726455122. Its totient is φ = 3914726455120.

The previous prime is 3914726455111. The next prime is 3914726455169. The reversal of 3914726455121 is 1215546274193.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2452293360400 + 1462433094721 = 1565980^2 + 1209311^2 .

It is a cyclic number.

It is not a de Polignac number, because 3914726455121 - 210 = 3914726454097 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 3914726455121.

It is not a weakly prime, because it can be changed into another prime (3914726455111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1957363227560 + 1957363227561.

It is an arithmetic number, because the mean of its divisors is an integer number (1957363227561).

Almost surely, 23914726455121 is an apocalyptic number.

It is an amenable number.

3914726455121 is a deficient number, since it is larger than the sum of its proper divisors (1).

3914726455121 is an equidigital number, since it uses as much as digits as its factorization.

3914726455121 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1814400, while the sum is 50.

The spelling of 3914726455121 in words is "three trillion, nine hundred fourteen billion, seven hundred twenty-six million, four hundred fifty-five thousand, one hundred twenty-one".