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39149124901 = 81349481249
BaseRepresentation
bin100100011101011110…
…000011110100100101
310202001100222121021221
4210131132003310211
51120134133444101
625552421340341
72554103033245
oct443536036445
9122040877257
1039149124901
111566a729a87
127706b676b1
1338cb9c8b83
141c7559bb25
151041e60aa1
hex91d783d25

39149124901 has 4 divisors (see below), whose sum is σ = 39149687500. Its totient is φ = 39148562304.

The previous prime is 39149124887. The next prime is 39149124919. The reversal of 39149124901 is 10942194193.

It is a happy number.

39149124901 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3030502500 + 36118622401 = 55050^2 + 190049^2 .

It is a cyclic number.

It is not a de Polignac number, because 39149124901 - 211 = 39149122853 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (39149124701) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 159276 + ... + 321973.

It is an arithmetic number, because the mean of its divisors is an integer number (9787421875).

Almost surely, 239149124901 is an apocalyptic number.

It is an amenable number.

39149124901 is a deficient number, since it is larger than the sum of its proper divisors (562599).

39149124901 is an equidigital number, since it uses as much as digits as its factorization.

39149124901 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 562598.

The product of its (nonzero) digits is 69984, while the sum is 43.

The spelling of 39149124901 in words is "thirty-nine billion, one hundred forty-nine million, one hundred twenty-four thousand, nine hundred one".

Divisors: 1 81349 481249 39149124901