Base | Representation |
---|---|
bin | 111001001010010011010… |
… | …110110100000111001001 |
3 | 111220112001010002222112112 |
4 | 321022103112310013021 |
5 | 1003324143004334123 |
6 | 12204310450352105 |
7 | 553536202662161 |
oct | 71122326640711 |
9 | 14815033088475 |
10 | 3928072339913 |
11 | 1284982481a97 |
12 | 53535358b635 |
13 | 2265531b4617 |
14 | d81966dd5a1 |
15 | 6c2a1525d78 |
hex | 392935b41c9 |
3928072339913 has 2 divisors, whose sum is σ = 3928072339914. Its totient is φ = 3928072339912.
The previous prime is 3928072339837. The next prime is 3928072339927. The reversal of 3928072339913 is 3199332708293.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3586751152384 + 341321187529 = 1893872^2 + 584227^2 .
It is a cyclic number.
It is not a de Polignac number, because 3928072339913 - 210 = 3928072338889 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (3928072239913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1964036169956 + 1964036169957.
It is an arithmetic number, because the mean of its divisors is an integer number (1964036169957).
Almost surely, 23928072339913 is an apocalyptic number.
It is an amenable number.
3928072339913 is a deficient number, since it is larger than the sum of its proper divisors (1).
3928072339913 is an equidigital number, since it uses as much as digits as its factorization.
3928072339913 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13226976, while the sum is 59.
The spelling of 3928072339913 in words is "three trillion, nine hundred twenty-eight billion, seventy-two million, three hundred thirty-nine thousand, nine hundred thirteen".
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