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393155145041 is a prime number
BaseRepresentation
bin1011011100010011101…
…11110110110101010001
31101120210122202201012012
411232021313312311101
522420140204120131
6500340223112305
740255515410441
oct5561167666521
91346718681165
10393155145041
1114181091457a
1264242a42695
132b0c75160c9
14150590b0121
15a360a2852b
hex5b89df6d51

393155145041 has 2 divisors, whose sum is σ = 393155145042. Its totient is φ = 393155145040.

The previous prime is 393155144951. The next prime is 393155145067. The reversal of 393155145041 is 140541551393.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 392458396225 + 696748816 = 626465^2 + 26396^2 .

It is a cyclic number.

It is not a de Polignac number, because 393155145041 - 226 = 393088036177 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 393155145041.

It is not a weakly prime, because it can be changed into another prime (393155142041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 196577572520 + 196577572521.

It is an arithmetic number, because the mean of its divisors is an integer number (196577572521).

Almost surely, 2393155145041 is an apocalyptic number.

It is an amenable number.

393155145041 is a deficient number, since it is larger than the sum of its proper divisors (1).

393155145041 is an equidigital number, since it uses as much as digits as its factorization.

393155145041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162000, while the sum is 41.

The spelling of 393155145041 in words is "three hundred ninety-three billion, one hundred fifty-five million, one hundred forty-five thousand, forty-one".