Base | Representation |
---|---|
bin | 111001001110011101100… |
… | …110111111111010001001 |
3 | 111220221120102112011222021 |
4 | 321032131212333322021 |
5 | 1003412320031300433 |
6 | 12210330021324441 |
7 | 554054663464432 |
oct | 71163546777211 |
9 | 14827512464867 |
10 | 3932539321993 |
11 | 1286864a20817 |
12 | 53619b566721 |
13 | 226ab579a599 |
14 | d849ba92489 |
15 | 6c46379122d |
hex | 3939d9bfe89 |
3932539321993 has 2 divisors, whose sum is σ = 3932539321994. Its totient is φ = 3932539321992.
The previous prime is 3932539321811. The next prime is 3932539322021. The reversal of 3932539321993 is 3991239352393.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3712608336969 + 219930985024 = 1926813^2 + 468968^2 .
It is an emirp because it is prime and its reverse (3991239352393) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3932539321993 - 233 = 3923949387401 is a prime.
It is not a weakly prime, because it can be changed into another prime (3932539321493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1966269660996 + 1966269660997.
It is an arithmetic number, because the mean of its divisors is an integer number (1966269660997).
Almost surely, 23932539321993 is an apocalyptic number.
It is an amenable number.
3932539321993 is a deficient number, since it is larger than the sum of its proper divisors (1).
3932539321993 is an equidigital number, since it uses as much as digits as its factorization.
3932539321993 is an evil number, because the sum of its binary digits is even.
The product of its digits is 31886460, while the sum is 61.
The spelling of 3932539321993 in words is "three trillion, nine hundred thirty-two billion, five hundred thirty-nine million, three hundred twenty-one thousand, nine hundred ninety-three".
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