Base | Representation |
---|---|
bin | 100100101100000110… |
… | …100001011110011011 |
3 | 10202200110220200212012 |
4 | 210230012201132123 |
5 | 1121140010110042 |
6 | 30033031140135 |
7 | 2563143454361 |
oct | 445406413633 |
9 | 122613820765 |
10 | 39394613147 |
11 | 15786260a2a |
12 | 777521464b |
13 | 393a81baa6 |
14 | 1c9a021631 |
15 | 10587a2e82 |
hex | 92c1a179b |
39394613147 has 2 divisors, whose sum is σ = 39394613148. Its totient is φ = 39394613146.
The previous prime is 39394613117. The next prime is 39394613227. The reversal of 39394613147 is 74131649393.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-39394613147 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 39394613095 and 39394613104.
It is not a weakly prime, because it can be changed into another prime (39394613117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19697306573 + 19697306574.
It is an arithmetic number, because the mean of its divisors is an integer number (19697306574).
Almost surely, 239394613147 is an apocalyptic number.
39394613147 is a deficient number, since it is larger than the sum of its proper divisors (1).
39394613147 is an equidigital number, since it uses as much as digits as its factorization.
39394613147 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1469664, while the sum is 50.
The spelling of 39394613147 in words is "thirty-nine billion, three hundred ninety-four million, six hundred thirteen thousand, one hundred forty-seven".
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