Base | Representation |
---|---|
bin | 111001010101101101011… |
… | …000110011101111111010 |
3 | 111221200122200200021200220 |
4 | 321111231120303233322 |
5 | 1004024233434333034 |
6 | 12214054053240510 |
7 | 554451544223532 |
oct | 71255530635772 |
9 | 14850580607626 |
10 | 3940320230394 |
11 | 128a098056429 |
12 | 5377b1333136 |
13 | 2277558005b2 |
14 | d89d92084c2 |
15 | 6c76b910749 |
hex | 3956d633bfa |
3940320230394 has 32 divisors (see below), whose sum is σ = 8093773758336. Its totient is φ = 1277919115200.
The previous prime is 3940320230347. The next prime is 3940320230437. The reversal of 3940320230394 is 4930320230493.
It is a super-3 number, since 3×39403202303943 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16330659 + ... + 16570185.
It is an arithmetic number, because the mean of its divisors is an integer number (252930429948).
Almost surely, 23940320230394 is an apocalyptic number.
3940320230394 is an abundant number, since it is smaller than the sum of its proper divisors (4153453527942).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3940320230394 is a wasteful number, since it uses less digits than its factorization.
3940320230394 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 313670.
The product of its (nonzero) digits is 419904, while the sum is 42.
Subtracting 3940320230394 from its reverse (4930320230493), we obtain a palindrome (990000000099).
It can be divided in two parts, 3940320 and 230394, that added together give a palindrome (4170714).
The spelling of 3940320230394 in words is "three trillion, nine hundred forty billion, three hundred twenty million, two hundred thirty thousand, three hundred ninety-four".
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