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394041433 is a prime number
BaseRepresentation
bin10111011111001…
…001100001011001
31000110110101020011
4113133021201121
51301333311213
6103033401521
712523203562
oct2737114131
91013411204
10394041433
11192476185
12abb692a1
1363836416
143a493169
15248d803d
hex177c9859

394041433 has 2 divisors, whose sum is σ = 394041434. Its totient is φ = 394041432.

The previous prime is 394041407. The next prime is 394041457. The reversal of 394041433 is 334140493.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 336098889 + 57942544 = 18333^2 + 7612^2 .

It is a cyclic number.

It is not a de Polignac number, because 394041433 - 29 = 394040921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 394041395 and 394041404.

It is not a weakly prime, because it can be changed into another prime (394041463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 197020716 + 197020717.

It is an arithmetic number, because the mean of its divisors is an integer number (197020717).

Almost surely, 2394041433 is an apocalyptic number.

It is an amenable number.

394041433 is a deficient number, since it is larger than the sum of its proper divisors (1).

394041433 is an equidigital number, since it uses as much as digits as its factorization.

394041433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 31.

The square root of 394041433 is about 19850.4768960345. The cubic root of 394041433 is about 733.1293898211.

The spelling of 394041433 in words is "three hundred ninety-four million, forty-one thousand, four hundred thirty-three".