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3941400778657 is a prime number
BaseRepresentation
bin111001010110101101110…
…010110001011110100001
3111221210102222220211020221
4321112231302301132201
51004033442044404112
612214353213203041
7554520404563156
oct71265562613641
914853388824227
103941400778657
11128a5a1a95321
12537a53190481
13227898630574
14d8a9c92222d
156c7d1702e07
hex395adcb17a1

3941400778657 has 2 divisors, whose sum is σ = 3941400778658. Its totient is φ = 3941400778656.

The previous prime is 3941400778643. The next prime is 3941400778723. The reversal of 3941400778657 is 7568770041493.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2781420082081 + 1159980696576 = 1667759^2 + 1077024^2 .

It is an emirp because it is prime and its reverse (7568770041493) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3941400778657 - 235 = 3907041040289 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3941400778595 and 3941400778604.

It is not a weakly prime, because it can be changed into another prime (3941400775657) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1970700389328 + 1970700389329.

It is an arithmetic number, because the mean of its divisors is an integer number (1970700389329).

Almost surely, 23941400778657 is an apocalyptic number.

It is an amenable number.

3941400778657 is a deficient number, since it is larger than the sum of its proper divisors (1).

3941400778657 is an equidigital number, since it uses as much as digits as its factorization.

3941400778657 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 35562240, while the sum is 61.

The spelling of 3941400778657 in words is "three trillion, nine hundred forty-one billion, four hundred million, seven hundred seventy-eight thousand, six hundred fifty-seven".