Base | Representation |
---|---|
bin | 111001010111110000100… |
… | …100111010111101101101 |
3 | 111221220100002020012011111 |
4 | 321113300210322331231 |
5 | 1004043240413032343 |
6 | 12215100320152021 |
7 | 554560231306636 |
oct | 71276044727555 |
9 | 14856302205144 |
10 | 3942521220973 |
11 | 12900174a2205 |
12 | 538106468611 |
13 | 227a167baa9a |
14 | d8b6766288d |
15 | 6c849c75c9d |
hex | 395f093af6d |
3942521220973 has 4 divisors (see below), whose sum is σ = 3962332885600. Its totient is φ = 3922709556348.
The previous prime is 3942521220961. The next prime is 3942521220977. The reversal of 3942521220973 is 3790221252493.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 3942521220973 - 217 = 3942521089901 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3942521220977) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9905832015 + ... + 9905832412.
It is an arithmetic number, because the mean of its divisors is an integer number (990583221400).
Almost surely, 23942521220973 is an apocalyptic number.
It is an amenable number.
3942521220973 is a deficient number, since it is larger than the sum of its proper divisors (19811664627).
3942521220973 is a wasteful number, since it uses less digits than its factorization.
3942521220973 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19811664626.
The product of its (nonzero) digits is 1632960, while the sum is 49.
The spelling of 3942521220973 in words is "three trillion, nine hundred forty-two billion, five hundred twenty-one million, two hundred twenty thousand, nine hundred seventy-three".
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