Base | Representation |
---|---|
bin | 100100101111101110… |
… | …111100001101001001 |
3 | 10202211201120002211211 |
4 | 210233232330031021 |
5 | 1121301104240131 |
6 | 30043045053121 |
7 | 2564513361661 |
oct | 445756741511 |
9 | 122751502754 |
10 | 39455540041 |
11 | 15807695235 |
12 | 77916b71a1 |
13 | 394a3318c8 |
14 | 1ca41611a1 |
15 | 105dcda5b1 |
hex | 92fbbc349 |
39455540041 has 2 divisors, whose sum is σ = 39455540042. Its totient is φ = 39455540040.
The previous prime is 39455540021. The next prime is 39455540051. The reversal of 39455540041 is 14004555493.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 31481050041 + 7974490000 = 177429^2 + 89300^2 .
It is an emirp because it is prime and its reverse (14004555493) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 39455540041 - 219 = 39455015753 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 39455539976 and 39455540003.
It is not a weakly prime, because it can be changed into another prime (39455540021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19727770020 + 19727770021.
It is an arithmetic number, because the mean of its divisors is an integer number (19727770021).
Almost surely, 239455540041 is an apocalyptic number.
It is an amenable number.
39455540041 is a deficient number, since it is larger than the sum of its proper divisors (1).
39455540041 is an equidigital number, since it uses as much as digits as its factorization.
39455540041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216000, while the sum is 40.
The spelling of 39455540041 in words is "thirty-nine billion, four hundred fifty-five million, five hundred forty thousand, forty-one".
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