3951001 has 2 divisors, whose sum is σ = 3951002. Its totient is φ = 3951000.

The previous prime is 3950951. The next prime is 3951023. The reversal of 3951001 is 1001593.

3951001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3459600 + 491401 = 1860^2 + 701^2 .

It is an emirp because it is prime and its reverse (1001593) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3951001 - 2¹¹ = 3948953 is a prime.

It is a super-2 number, since 2×3951001² = 31220817804002, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 3951001.

It is not a weakly prime, because it can be changed into another prime (3951071) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1975500 + 1975501.

It is an arithmetic number, because the mean of its divisors is an integer number (1975501).

Almost surely, 2^3951001 is an apocalyptic number.

It is an amenable number.

3951001 is a deficient number, since it is larger than the sum of its proper divisors (1).

3951001 is an equidigital number, since it uses as much as digits as its factorization.

3951001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 135, while the sum is 19.

The square root of 3951001 is about 1987.7125043627. The cubic root of 3951001 is about 158.0892648395.

Adding to 3951001 its reverse (1001593), we get a palindrome (4952594).

It can be divided in two parts, 39 and 51001, that added together give a triangular number (51040 = T₃₁₉).

The spelling of 3951001 in words is "three million, nine hundred fifty-one thousand, one".