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395113503 = 3131704501
BaseRepresentation
bin10111100011001…
…111010000011111
31000112110211211110
4113203033100133
51302122113003
6103112353103
712535260261
oct2743172037
91015424743
10395113503
11193038694
12b03a5793
1363b20395
143a691b31
1524a4aa03
hex178cf41f

395113503 has 4 divisors (see below), whose sum is σ = 526818008. Its totient is φ = 263409000.

The previous prime is 395113471. The next prime is 395113513. The reversal of 395113503 is 305311593.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 305311593 = 3101770531.

It is not a de Polignac number, because 395113503 - 25 = 395113471 is a prime.

It is a super-2 number, since 2×3951135032 = 312229360505862018, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (395113513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65852248 + ... + 65852253.

It is an arithmetic number, because the mean of its divisors is an integer number (131704502).

Almost surely, 2395113503 is an apocalyptic number.

395113503 is a deficient number, since it is larger than the sum of its proper divisors (131704505).

395113503 is a wasteful number, since it uses less digits than its factorization.

395113503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 131704504.

The product of its (nonzero) digits is 6075, while the sum is 30.

The square root of 395113503 is about 19877.4621871103. The cubic root of 395113503 is about 733.7936637113.

The spelling of 395113503 in words is "three hundred ninety-five million, one hundred thirteen thousand, five hundred three".

Divisors: 1 3 131704501 395113503