Base | Representation |
---|---|
bin | 111001100001101000111… |
… | …010001100101010101001 |
3 | 111222220201102111221202211 |
4 | 321201220322030222221 |
5 | 1004232002234432032 |
6 | 12224013131125121 |
7 | 555414150400663 |
oct | 71415072145251 |
9 | 14886642457684 |
10 | 3953129999017 |
11 | 1294570910171 |
12 | 53a1872a37a1 |
13 | 228a17658444 |
14 | d94925b5533 |
15 | 6cc6b2d7747 |
hex | 39868e8caa9 |
3953129999017 has 2 divisors, whose sum is σ = 3953129999018. Its totient is φ = 3953129999016.
The previous prime is 3953129999003. The next prime is 3953129999023. The reversal of 3953129999017 is 7109999213593.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3120554047081 + 832575951936 = 1766509^2 + 912456^2 .
It is a cyclic number.
It is not a de Polignac number, because 3953129999017 - 215 = 3953129966249 is a prime.
It is not a weakly prime, because it can be changed into another prime (3953129999057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1976564999508 + 1976564999509.
It is an arithmetic number, because the mean of its divisors is an integer number (1976564999509).
Almost surely, 23953129999017 is an apocalyptic number.
It is an amenable number.
3953129999017 is a deficient number, since it is larger than the sum of its proper divisors (1).
3953129999017 is an equidigital number, since it uses as much as digits as its factorization.
3953129999017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 37200870, while the sum is 67.
The spelling of 3953129999017 in words is "three trillion, nine hundred fifty-three billion, one hundred twenty-nine million, nine hundred ninety-nine thousand, seventeen".
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