Base | Representation |
---|---|
bin | 101100111101000000001001… |
… | …1101101101011011101000001 |
3 | 1220212001001000001221111120212 |
4 | 1121322000103231223131001 |
5 | 403311413141132134023 |
6 | 3520545505032243505 |
7 | 146200405632224024 |
oct | 13172002355533501 |
9 | 1825031001844525 |
10 | 395412199880513 |
11 | 104a99410504312 |
12 | 38421649840595 |
13 | 13c832974a143a |
14 | 6d900a44331bb |
15 | 30aa8a33a9e78 |
hex | 167a013b6b741 |
395412199880513 has 2 divisors, whose sum is σ = 395412199880514. Its totient is φ = 395412199880512.
The previous prime is 395412199880491. The next prime is 395412199880549. The reversal of 395412199880513 is 315088991214593.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 275335049527729 + 120077150352784 = 16593223^2 + 10957972^2 .
It is a cyclic number.
It is not a de Polignac number, because 395412199880513 - 248 = 113937223169857 is a prime.
It is a super-3 number, since 3×3954121998805133 (a number of 45 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (395412199880213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 197706099940256 + 197706099940257.
It is an arithmetic number, because the mean of its divisors is an integer number (197706099940257).
Almost surely, 2395412199880513 is an apocalyptic number.
It is an amenable number.
395412199880513 is a deficient number, since it is larger than the sum of its proper divisors (1).
395412199880513 is an equidigital number, since it uses as much as digits as its factorization.
395412199880513 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 83980800, while the sum is 68.
The spelling of 395412199880513 in words is "three hundred ninety-five trillion, four hundred twelve billion, one hundred ninety-nine million, eight hundred eighty thousand, five hundred thirteen".
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