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395412199880513 is a prime number
BaseRepresentation
bin101100111101000000001001…
…1101101101011011101000001
31220212001001000001221111120212
41121322000103231223131001
5403311413141132134023
63520545505032243505
7146200405632224024
oct13172002355533501
91825031001844525
10395412199880513
11104a99410504312
1238421649840595
1313c832974a143a
146d900a44331bb
1530aa8a33a9e78
hex167a013b6b741

395412199880513 has 2 divisors, whose sum is σ = 395412199880514. Its totient is φ = 395412199880512.

The previous prime is 395412199880491. The next prime is 395412199880549. The reversal of 395412199880513 is 315088991214593.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 275335049527729 + 120077150352784 = 16593223^2 + 10957972^2 .

It is a cyclic number.

It is not a de Polignac number, because 395412199880513 - 248 = 113937223169857 is a prime.

It is a super-3 number, since 3×3954121998805133 (a number of 45 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (395412199880213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 197706099940256 + 197706099940257.

It is an arithmetic number, because the mean of its divisors is an integer number (197706099940257).

Almost surely, 2395412199880513 is an apocalyptic number.

It is an amenable number.

395412199880513 is a deficient number, since it is larger than the sum of its proper divisors (1).

395412199880513 is an equidigital number, since it uses as much as digits as its factorization.

395412199880513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 83980800, while the sum is 68.

The spelling of 395412199880513 in words is "three hundred ninety-five trillion, four hundred twelve billion, one hundred ninety-nine million, eight hundred eighty thousand, five hundred thirteen".