Base | Representation |
---|---|
bin | 111001100010111001101… |
… | …110101001101000000011 |
3 | 112000001012220221012110122 |
4 | 321202321232221220003 |
5 | 1004242241344121103 |
6 | 12224355445250455 |
7 | 555462563524025 |
oct | 71427156515003 |
9 | 15001186835418 |
10 | 3954485926403 |
11 | 12950a7237511 |
12 | 53a4a5403a2b |
13 | 228ba254573c |
14 | d95806d4015 |
15 | 6ccea373b38 |
hex | 398b9ba9a03 |
3954485926403 has 2 divisors, whose sum is σ = 3954485926404. Its totient is φ = 3954485926402.
The previous prime is 3954485926393. The next prime is 3954485926463. The reversal of 3954485926403 is 3046295844593.
3954485926403 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (3046295844593) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3954485926403 - 232 = 3950190959107 is a prime.
It is not a weakly prime, because it can be changed into another prime (3954485926463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1977242963201 + 1977242963202.
It is an arithmetic number, because the mean of its divisors is an integer number (1977242963202).
Almost surely, 23954485926403 is an apocalyptic number.
3954485926403 is a deficient number, since it is larger than the sum of its proper divisors (1).
3954485926403 is an equidigital number, since it uses as much as digits as its factorization.
3954485926403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 111974400, while the sum is 62.
The spelling of 3954485926403 in words is "three trillion, nine hundred fifty-four billion, four hundred eighty-five million, nine hundred twenty-six thousand, four hundred three".
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