Base | Representation |
---|---|
bin | 1110101110111110… |
… | …1101010010110001 |
3 | 101012122022112121221 |
4 | 3223233231102301 |
5 | 31100004331144 |
6 | 1452244345041 |
7 | 200004144352 |
oct | 35357552261 |
9 | 11178275557 |
10 | 3955152049 |
11 | 174a642302 |
12 | 9246a5181 |
13 | 4b054b374 |
14 | 2973dbd29 |
15 | 182366d84 |
hex | ebbed4b1 |
3955152049 has 2 divisors, whose sum is σ = 3955152050. Its totient is φ = 3955152048.
The previous prime is 3955152041. The next prime is 3955152067. The reversal of 3955152049 is 9402515593.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3906250000 + 48902049 = 62500^2 + 6993^2 .
It is an emirp because it is prime and its reverse (9402515593) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3955152049 - 23 = 3955152041 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3955151996 and 3955152014.
It is not a weakly prime, because it can be changed into another prime (3955152041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1977576024 + 1977576025.
It is an arithmetic number, because the mean of its divisors is an integer number (1977576025).
Almost surely, 23955152049 is an apocalyptic number.
It is an amenable number.
3955152049 is a deficient number, since it is larger than the sum of its proper divisors (1).
3955152049 is an equidigital number, since it uses as much as digits as its factorization.
3955152049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 243000, while the sum is 43.
The square root of 3955152049 is about 62889.9995945301. Note that the first 3 decimals coincide. The cubic root of 3955152049 is about 1581.4461002057.
The spelling of 3955152049 in words is "three billion, nine hundred fifty-five million, one hundred fifty-two thousand, forty-nine".
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