Search a number
-
+
39554045521 is a prime number
BaseRepresentation
bin100100110101100110…
…101101011001010001
310210002120220200221221
4210311212231121101
51122001313424041
630100524245041
72600120560654
oct446546553121
9123076820857
1039554045521
1115858255921
1277ba6a0781
133964871083
141cb328389b
1510677972d1
hex9359ad651

39554045521 has 2 divisors, whose sum is σ = 39554045522. Its totient is φ = 39554045520.

The previous prime is 39554045501. The next prime is 39554045551. The reversal of 39554045521 is 12554045593.

39554045521 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 38215949121 + 1338096400 = 195489^2 + 36580^2 .

It is an emirp because it is prime and its reverse (12554045593) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 39554045521 - 213 = 39554037329 is a prime.

It is a super-2 number, since 2×395540455212 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (39554045501) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19777022760 + 19777022761.

It is an arithmetic number, because the mean of its divisors is an integer number (19777022761).

Almost surely, 239554045521 is an apocalyptic number.

It is an amenable number.

39554045521 is a deficient number, since it is larger than the sum of its proper divisors (1).

39554045521 is an equidigital number, since it uses as much as digits as its factorization.

39554045521 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 540000, while the sum is 43.

The spelling of 39554045521 in words is "thirty-nine billion, five hundred fifty-four million, forty-five thousand, five hundred twenty-one".