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3971350097045 = 5794270019409
BaseRepresentation
bin111001110010100110111…
…010010110110010010101
3112001122202012211211112022
4321302212322112302111
51010031311111101140
612240225115102525
7556630520565212
oct71624672266225
915048665754468
103971350097045
1112a1270662521
12541811141a45
1322a65c35bc36
14da300336b09
156d485b6a0b5
hex39ca6e96c95

3971350097045 has 4 divisors (see below), whose sum is σ = 4765620116460. Its totient is φ = 3177080077632.

The previous prime is 3971350097003. The next prime is 3971350097083. The reversal of 3971350097045 is 5407900531793.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 554497665316 + 3416852431729 = 744646^2 + 1848473^2 .

It is a cyclic number.

It is not a de Polignac number, because 3971350097045 - 26 = 3971350096981 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 397135009700 + ... + 397135009709.

It is an arithmetic number, because the mean of its divisors is an integer number (1191405029115).

Almost surely, 23971350097045 is an apocalyptic number.

It is an amenable number.

3971350097045 is a deficient number, since it is larger than the sum of its proper divisors (794270019415).

3971350097045 is an equidigital number, since it uses as much as digits as its factorization.

3971350097045 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 794270019414.

The product of its (nonzero) digits is 3572100, while the sum is 53.

The spelling of 3971350097045 in words is "three trillion, nine hundred seventy-one billion, three hundred fifty million, ninety-seven thousand, forty-five".

Divisors: 1 5 794270019409 3971350097045