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39794130113 is a prime number
BaseRepresentation
bin100101000011111010…
…100011110011000001
310210201022200021002212
4211003322203303001
51122444244130423
630140422151505
72606064345023
oct450372436301
9123638607085
1039794130113
1115970826a41
127866b82595
1339a252156a
141cd70dc013
15107d8bd578
hex943ea3cc1

39794130113 has 2 divisors, whose sum is σ = 39794130114. Its totient is φ = 39794130112.

The previous prime is 39794130067. The next prime is 39794130203. The reversal of 39794130113 is 31103149793.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 33199390849 + 6594739264 = 182207^2 + 81208^2 .

It is an emirp because it is prime and its reverse (31103149793) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 39794130113 - 228 = 39525694657 is a prime.

It is not a weakly prime, because it can be changed into another prime (39794130413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19897065056 + 19897065057.

It is an arithmetic number, because the mean of its divisors is an integer number (19897065057).

Almost surely, 239794130113 is an apocalyptic number.

It is an amenable number.

39794130113 is a deficient number, since it is larger than the sum of its proper divisors (1).

39794130113 is an equidigital number, since it uses as much as digits as its factorization.

39794130113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 61236, while the sum is 41.

The spelling of 39794130113 in words is "thirty-nine billion, seven hundred ninety-four million, one hundred thirty thousand, one hundred thirteen".