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3981214740300 = 22352727120633391
BaseRepresentation
bin111001111011110010111…
…000111110111101001100
3112002121012200220122002220
4321323302320332331030
51010212011433142200
612244540024415340
7560430132636120
oct71736270767514
915077180818086
103981214740300
1112a5472a26a56
12543704917550
1322b571ca6655
14da998503580
156d861bdc4a0
hex39ef2e3ef4c

3981214740300 has 288 divisors, whose sum is σ = 13223430979584. Its totient is φ = 905927328000.

The previous prime is 3981214740253. The next prime is 3981214740301. The reversal of 3981214740300 is 30474121893.

It is a Harshad number since it is a multiple of its sum of digits (42).

It is not an unprimeable number, because it can be changed into a prime (3981214740301) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 1174051605 + ... + 1174054995.

Almost surely, 23981214740300 is an apocalyptic number.

3981214740300 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 3981214740300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (6611715489792).

3981214740300 is an abundant number, since it is smaller than the sum of its proper divisors (9242216239284).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3981214740300 is a wasteful number, since it uses less digits than its factorization.

3981214740300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5749 (or 5742 counting only the distinct ones).

The product of its (nonzero) digits is 145152, while the sum is 42.

The spelling of 3981214740300 in words is "three trillion, nine hundred eighty-one billion, two hundred fourteen million, seven hundred forty thousand, three hundred".